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A scientist who studies teenage behavior was interested in determining if teenagers spend more time playing computer games then they did in the 1990s. In 1990s, the average amount of time spent playing computer games was 10. 2 hours per week. Is the amount of time greater than that for this year? ten students were surveyed and asked how many hours they spent playing video games. The test statistics is equal to 0. 45. What is the p-value?.

Sagot :

Varshamittal029idn

From the hypothesis test, it is found that that the p value is of  0.6683

At the null hypothesis, we test if the mean is still the same, that is, of 10.2 hours per week, thus:

H₀ : µ > 10.2

At the alternative hypothesis, we test if the mean has increased, that is, if it is greater than 10.2 hours per week, thus:

H₁: µ > 10.2

10 students were surveyed, so there are 9 df (degree of freedom).

The test statistic is t = 0.45, and it is a one-tailed test, as we are testing if the mean is greater than a value

Thus, p test:

X = 10.2 hours

n = 10

test statistics = 0.45

Thus, using a t-distribution calculator, the p-value of the test is of 0.6683

Pvalue = 0.6683

p value is greater is than 0.10 which indicates that the amount of time is not greater than 10.2 hours for this year.

Hence we get the value of p as 0.6683.

Learn more about Statistics here:

brainly.com/question/14724376

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