Answered

Discover a wealth of knowledge and get your questions answered at IDNLearn.com. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.

the radius of a right circular cone is increasing at a rate of 1.3 in/s while its height is decreasing at a rate of 2.1 in/s. at what rate is the volume of the cone changing when the radius is 122 in. and the height is 147 in.?

Sagot :

Varshamittal029idn

We need to know about the rate of change to solve the problem. The rate of change of the volume of the cone is 16097.52 cubic in/s

The rate of change of a quantity is the rate at which it either increases or decreases. In this question we know that the radius is increasing at a rate of 1.3 in/s, height is decreasing at a rate of 2.1 in/s, we need to find the rate of change of volume given the radius is 122 in and the height is 147 in.

volume of a cone=[tex]\pi r^{2}[/tex]h/3

dV/dt=[tex]\pi[/tex]/3(2rh dr/dt+[tex]r^{2}[/tex] dh/dt)=[tex]\pi[/tex]/3(2x122x147x1.3 -122x122x2.1)=16097.52

Therefore the change in volume is 16097.52 cubic in/s.

Learn more about rate of change here:

https://brainly.com/question/20884505

#SPJ4

Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.