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The number of grams of solid magnesium chloride, mgcl2 needed to make 250 ml of 0. 50M solution is 12g
Since 1-M solution contains 1 mole of solute, then 0.50M magnesium chloride solution will contain 0.50 moles of magnesium chloride.
We find the number of moles that will be equivalent to 250 ml or 0.25L of solution:
moles of MgCl[tex]_{2}[/tex]=(0.25L*0.50MgCl[tex]_{2}[/tex])
moles of MgCl[tex]_{2}[/tex]=0.125 moles MgCl[tex]_{2}[/tex] in 250ml or 0.25L
We now calculate the number of grams of solid magnesium chloride needed:
To convert 0.125 moles MgCl[tex]_{2}[/tex] to grams, we use the molar mass compound which is 95.211 g for magnesium chloride
So. 1 mole MgCl[tex]_{2}[/tex]=95.211g
0.125 moles MgCl[tex]_{2}[/tex]=?
=(0.125 moles MgCl[tex]_{2}[/tex]*95.211g)/1 mole MgCl[tex]_{2}[/tex]
=11.90g
=12g
Hence the number of grams needed is 12g
To learn more about Molarity, click here:
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