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Answer:
64822
Step-by-step explanation:
Half-life model:
[tex]P=P_o* \left(\frac{1}{2}\right)^{\frac{t}{D}}[/tex]
[tex]P_o[/tex] is the initial value, D is the time taken for the quantity to reduce half-life and t is the given time period.
[tex]\sf P_o = 259,288 \ grams\\\\D = 1 \ hour\\\\t = 2 \ hours[/tex]
[tex]P = 259,288*(\frac{1}{2})^\frac{2}{1}\\\\P = 259,288*(\frac{1}{2})^2\\\\P = 259,288*\frac{1}{4}\\\\P = 64822[/tex]