Answered

Get the information you need quickly and easily with IDNLearn.com. Ask your questions and get detailed, reliable answers from our community of knowledgeable experts.

The function g(x) is continuous on the closed interval [8, 10] and differentiable on the open interval
(8, 10). The value x = 8.5 satisfies the conditions of the Mean Value Theorem on the interval [8, 10].
What is g(10) given g'(8.5) = -9 and g(8) = 6?

Sagot :

Semsee45idn

Answer:

g(10) = -12

Step-by-step explanation:

Mean Value Theorem

If f is continuous on [a, b] and differentiable on (a, b), then there is a number c  such that a < c < b and:

[tex]f'(c)=\dfrac{f(b)-f(a)}{b-a}[/tex]

We are told that the function g(x) is continuous on the closed interval [8, 10] and differentiable on the open interval (8, 10).

Therefore:

  • a = 8
  • b = 10

Given:

  • g'(8.5) = -9
  • g(8) = 6

As 8 < 8.5 < 10 then c = 8.5:

[tex]\begin{aligned} \implies g'(8.5)=\dfrac{g(10)-g(8)}{10-8}&=-9\\\\\dfrac{g(10)-6}{2}&=-9\\\\g(10)-6&=-18\\\\g(10)&=-12\end{aligned}[/tex]

Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.