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Graph the line with slope 2/3 passing through the point (3,2)
so the line is in slope intercept form y=mx+b, m=slope and b=y intercept we know the slope so just solve for b y=2/3x+b subsitute 3 for x and 2 for y 2=2/3(3)+b 2=2+b subtract 2 from both sdies 0=b so the equaiton is y=2/3x+0 or just simply y=2/3x here is the graph just input values for x and get y values exg x=3 y=2 x=6 y=4 x=0 y=0 x=-3 y=-2
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