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Sagot :
Divide the problem into 3 steps. 1.Eliminate one variable. 2. Solve for the remaining variable. 3. Use that information to solve for the second variable.
1.
Multiply the top equation by -3
-3x+9y=-81
3x-3y=39
If you add these two equations together, you are left with
6y=-42
2.
Solve for y by dividing both sides by 6
y=-7
3.
Plug -7 in for y in the either equation. I'll use the top one. It's just simpler.
x-3(-7)=27
x=6
Check your work plugging both variables into both equations to see if they are still true.
1.
Multiply the top equation by -3
-3x+9y=-81
3x-3y=39
If you add these two equations together, you are left with
6y=-42
2.
Solve for y by dividing both sides by 6
y=-7
3.
Plug -7 in for y in the either equation. I'll use the top one. It's just simpler.
x-3(-7)=27
x=6
Check your work plugging both variables into both equations to see if they are still true.
[tex]x-3y=27 \ \ \ |\times (-1) \\
3x-3y=39 \\ \\
-x+3y=-27 \\
\underline{3x-3y=39 \ \ \ \ \ } \\
3x-x=39-27 \\
2x=12 \\ x=\frac{12}{2} \\
x=6 \\ \\
x-3y=27 \\
6-3y=27 \\
-3y=27-6 \\
-3y=21 \\
y=\frac{21}{-3} \\
y=-7 \\ \\
\boxed{(x,y)=(6,-7)}[/tex]
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