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Sodium metal reacts with aluminum chloride to produce sodium chloride and aluminum. The balanced reaction is: 3 Na(s) + AlCl3(aq) --> 3 NaCl(aq) + Al(s). How many moles of aluminum metal could you get when 12.0 grams of sodium react with excess aluminum chloride?
First convert 12.0g of Na to moles using the grams to moles conversation and you get about .5219 moles (I didn't use significant figures). Divide that number by 3 because that is the coefficient of Na and you will get about .17398 moles, which is how many moles are in 1. Since Al has a coefficient of 1, .17398 woild be your final answer
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