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given cos(-x) = 3/4 and tanx= √7/3, find sin(-x)

Sagot :

The trigonometric function sin(-x) is -√7/4 when cos(-x) = 3/4 and tanx= √7/3

What is Trigonometry?

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Given,

cos(-x) =cosx= 3/4

and tanx=

We need to find sin(-x)

tank is ratio of sinx and cosx

We know that tanx=sinx/cosx

√7/3=sinx/3/4

Apply cross multiplication

sinx=√7/3.3/4

sinx=√7/4

sin(-x)=-sinx=-√7/4

Hence, Trigonometric function sin(-x) is -√7/4 when cos(-x) = 3/4 and tanx= √7/3

To learn more on trigonometry click:

https://brainly.com/question/25122835

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