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p5.7 during a test, the four-cycle, 15.649 l (955 in3) engine in a large tractor consumes 73 l/h (19.3 gal/h) of diesel fuel while running at 2100 r/min (rpm) and producing 1160 nm (856 lb-ft) of torque. the imep during the test is 1110 kpa (161 psi). the fuel density is 0.835 kg/l (7.0 lb/gal), and its heating value is 45,434 kj/kg (19,533 btu/lb). calculate:

Sagot :

During a test, the four-cycle FEP=1051.44 hp, IP=407.43 HP and brake power BP= 342.26 hr

Given : Displacemen Volume Vs = 955 in³

density S: 7 lbigat

ΔV = volumetric fuel consumption = 19.3 gal/h

N = 2100 pm

Ti ( Torque ) = 856 lb-it

Calorific value ( C . V ) = 19 ,533 BTU /lb

( After cut off ) 7F = 163 lb- ft .

Fuel consumption ( mf ) = δx ΔV

= 7 x 19 .3

mf = 135 . 1 lb/ br

Now Brake power :

BP = TixN/5252(hp )

B. P =

85 6X 2100/5252

= 342 . 26 hp

B . P = 342 . 26 hp

Now Fuel equivalent power

fEr :my x C . V

135. 1 ( eb / hr ) x 19, 533 ( BTU/ RD )

135. 1 X19533/60 x 41.83

FEP

= 1051.44 hp

Learn more about Brake power here:

https://brainly.com/question/13279330

#SPJ4

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