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Answer: The maximum velocity of the object if the object bounces 3.45 cm above and below its equilibrium position is 4.62 m/s.
Reason:
The maximum velocity of the object is 4.62 m/s. This can be calculated by using the equation v = sqrt(2 * g * x), where g is the acceleration due to gravity (9.8 m/s2) and x is the displacement from the equilibrium position (3.45 cm), or 0.0345 m.
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