IDNLearn.com provides a collaborative platform for sharing and gaining knowledge. Find the information you need quickly and easily with our reliable and thorough Q&A platform.
Sagot :
The angle of banking of the road is 11° and The minimum coefficient of friction between tires and road is 0.19
The attached free-body diagram to the query illustrates the forces operating on the car if the road is banked at an angle without utilizing friction (i.e., frictionless road).
mg = N cos θ (Eqn 1)
mg = weight of the car.
N = normal reaction of the plane on the car
And in the direction parallel to the inclined plane,
(mv²/r) = N sin θ (Eqn 2)
(mv²/r) = force keeping the car in a circular motion
Divide (Eqn 2) by (Eqn 1)
(v²/gr) = Tan θ
v = velocity of car = 60 km/h = 16.667 m/s
g = acceleration due to gravity
r = 150 m
(16.667²/(9.8×150)) = Tan θ
θ = Tan⁻¹ (0.18896)
θ = 10.7° ≈ 11°
b) In the absence of banking, the force maintaining the car in a circular motion must be balanced by the frictional force of the road.
That is,
Fr = (mv²/r)
Fr = μN = μ mg
μ mg = mv²/r
μ = (v²/gr) = (16.667²/(9.8×150)) = 0.19
Know more about the coefficient of friction at:
https://brainly.com/question/19291861
#SPJJ4

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.