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find the capacitance of a parallel plate capacitor if the area of each plate is 0.1 m2 and the distance between the plates is 0.1 inch. the dielectric is air.

Sagot :

The capacitance of a parallel plate capacitor is 3.612×10⁻¹⁰ohm if the area of each plate is 0.1m² and distance between plate is 0.1inch.

Capacitance is the capacity of a material item or gadget to store electric charge. It is estimated by the adjustment of charge because of a distinction in electric potential, communicated as the proportion of those amounts. Regularly perceived are two firmly related thoughts of capacitance: self capacitance and shared capacitance.

An article that can be electrically charged shows self capacitance, for which the electric potential is estimated between the item and ground. Common capacitance is estimated between two parts, and is especially significant in the tasks of the capacitor, a gadget intended for this reason as a rudimentary straight electronic part.

We know that 1inch=2.54cm

Therefore,0.1inch=2.54×0.1cm=0.245cm=0.00245m

Now, we know that capacitance=∈[tex]_o[/tex]×A /d where

∈[tex]_o[/tex] is the permittivity of free space,

A is the area of cross-section,

d is the distance between two plates.

We know that value of ∈[tex]_o[/tex]=8.85×10⁻¹² Farad/meter

Therefore, C = (8.85×10⁻¹²×0.1)/0.00245

=>C=(8.85×10⁻¹³)/0.00245

=>C=3.612×10⁻¹⁰ohm

Hence, value of capacitance is 3.612×10⁻¹⁰ohm.

To know more about capacitance,visit here:

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