From health tips to tech hacks, find it all on IDNLearn.com. Our community is here to provide detailed and trustworthy answers to any questions you may have.
The probability that there will be at least 12 successes in the total 18 trials with 60% rate of success is ¹⁸C₁₂(0.6)¹²(0.4)⁶+¹⁸C₁₃(0.6)¹³(0.4)⁵+¹⁸C₁₄(0.6)¹⁴(0.4)⁴+ ¹⁸C₁₅(0.6)¹⁵(0.4)³ +¹⁸C₁₆(0.6)¹⁶(0.4)²+ ¹⁸C₁₇(0.6)¹⁷(0.4)¹+ ¹⁸C₁₈(0.6)¹⁸(0.4)⁰
Binomial Probability distribution, In probability theory and statistics, the binomial distribution with parameters n and p is the discrete probability distribution of the number of successes in a series of n independent experiments.
We have given that :
Rate of sucess (p) = 60% = 0.6
Rate of failure (q) = 1 - 0.6 = 0.4
Number of trials (n) = 18
We want to find P(there will be at least 12 sucess)
Use binomial distribution to find given mentioned probability.
X ~ Bin( 18, 0.6)
P (X= x ) = ⁿCₓ(p)ˣ(q)⁽ⁿ⁻ˣ⁾
Let, X= Number of success among 18
So that it suitable for binomial distribution with parameters are n and p.
P(there will be atleast 12 success)
= P(X>= 12)
18
= ∑ ⁿCₓ (p)ˣ(q)⁽ⁿ⁻ˣ⁾ =
x = 12
¹⁸C₁₂(0.6)¹²(0.4)⁶+¹⁸C₁₃(0.6)¹³(0.4)⁵+¹⁸C₁₄(0.6)¹⁴(0.4)⁴+ ¹⁸C₁₅(0.6)¹⁵(0.4)³ +¹⁸C₁₆(0.6)¹⁶(0.4)²+ ¹⁸C₁₇(0.6)¹⁷(0.4)¹+ ¹⁸C₁₈(0.6)¹⁸(0.4)⁰
= say x
Hence, the required probability is x
To learn more about binomial Probability distribution, refer:
https://brainly.com/question/15278907
#SPJ4