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Sagot :
With a pressure drop of 120 kpa/m, glycerin at 380 c flows through a horizontal pipe with a 9 mm diameter. The Reynolds number is 3.807 after the discharge.
pressure drop=32μVL/D²
120*10³=32*0.95*V*1/(9*10⁻³)²
Velocity V=0.329 m/sec
discharge =AV
=π(9*10⁻³)²/4*0.319
pressure drop=2.02*10⁻⁵ m³
then,
Reynolds number=VD/γ
=δVD/μ
1.26*10³*0.319*9*10⁻³/0.95
=3.807
By measuring the proportion of inertial and viscous forces, the Reynolds number aids in the prediction of flow patterns in various fluid flow scenarios. Laminar flow typically predominates in low Reynolds numbers flows while turbulent flow predominates in high Reynolds numbers flows.
Learn more about Reynolds number here:
https://brainly.com/question/12977616
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