IDNLearn.com offers a reliable platform for finding accurate and timely answers. Get the information you need from our community of experts who provide accurate and thorough answers to all your questions.
Sagot :
The probability that [tex]\bar{x}[/tex] < 1.57 for the given mean, standard deviation , and samples is equal to 0.0162.
As given in the question,
Normal distribution with mean 'μ' = 1.59 millimeters
Standard deviation 'σ' = 0.042 millimeters
Sample size 'n' = 20
standard error = σ /√n
= 0.042 / √20
= 0.00933
Probability that [tex]\bar{x}[/tex] < 1.57 is
X = 1.57
s = 0.0093
P( X < 1.57)
= P[ (X -μ)/s < ( 1.57 - 1.59)/ 0.0093]
= P ( z < -2.14 )
Using z - table p value is
= 0.01617
= 0.0162
Therefore, the probability for the [tex]\bar{x}[/tex] < 1.57 is equal to 0.0162.
The complete question is :
A factory makes components used in jet engines, including reinforced steel washers. the washers are required to have a very precise thickness. the thickness of the washers follow a normal distribution with mean 1.59 millimeters and standard deviation 0.042 millimeters. a technician randomly samples n = 20 washers and calculates the mean of their thicknesses, which is x¯. what is the probability that x¯<1.57?
Learn more about probability here
brainly.com/question/11234923
#SPJ4
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.