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Sagot :
If each side of a square is increasing at a rate of 7 cm/s, then the rate of increasing the area of the the square when the area of the square is 64 cm square is 112 centimeter square per second
The rate of change of length with respect to the time = 7 cm per second
That is
dl / dt = 7 cm per second
The area of the square = l^2
Where l is the length of the square
The rate of change area with respect to the time is
dA / dt = 2l dl/dt
The area is given that 64 centimeter square and the side will be 8 cm
Substitute the values in the equation
dA / dt = 2 × 8 × 7
= 112 centimeter square per second
Therefore, the rate of increasing the area is 112 centimeter square per second
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