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t the movie theatre, child admission is and adult admission is . on wednesday, twice as many adult tickets as child tickets were sold, for a total sales of . how many child tickets were sold that day?

Sagot :

The number of child ticket were sold on Wednesday is 236

The cost of child admission ticket = $6.10

The cost of adult admission ticket = $9.20

Consider the number of child ticket as x and the number of adult ticket as y

Twice times as many adult tickets as child tickets were sold

y = 2x

Then the equation will be

x + y = 707.70

Substitute the value of y in the equation

x + 2x = 707.70

Add the like terms

3x = 707.70

x = 707.70/3

Divide the terms

x = 235.9

x ≈ 236

Therefore, 236 child ticket were sold on that day

I have answered the question in general, as the given question is incomplete

The complete question is:

At the movie theatre, child admission is $6.10 and adult admission is $9.20 . On Wednesday, twice times as many adult tickets as child tickets were sold, for a total sales of $707.70 . How many child tickets were sold that day?

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