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a consumer organization estimates that over a 1-year period 17% of cars will need to be repaired once, 7% will need repairs twice, and 4% will require three or more repairs. what is the probability that a car chosen at random will need a) norepairs? b) nomorethanonerepair? c) some repairs?

Sagot :

The probability that a car chosen to random will need:

A) no repairs: 72%

B) No more than one repairs: 89%

C) some repairs: 11%

The total amount of cars that will need some type of repair is 28%; 17% will need to be repaired once + 7% will need to be repaired twice + 4% will need to be repaired more than two times.

The amount of cars that wouldn´t need any type of repairs is the total amount of cars minus the percentage that need some type of repair:                

                                   100% - 28% = 72%.

The amount of cars that will need no repairs or only one repair is the total amount of cars minus the percentage that need more than one of repair:

                             100% - (7% + 4%) = 89%.

The amount of cars that need some repairs is the sum of those cars that need two repairs plus those that need three or more repairs:

                                  7% + 4% = 11%

Learn more about Probability:

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