suppose 14c-labeled co2 is used to form malonyl-coa from acetyl-coa. if this labeled malonyl-coa is used for palmitate synthesis, which carbon atom(s) in the fatty acid would be radiolabeled?

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01-12-2022
Chemistry

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suppose 14c-labeled co2 is used to form malonyl-coa from acetyl-coa. if this labeled malonyl-coa is used for palmitate synthesis, which carbon atom(s) in the fatty acid would be radiolabeled?

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Rafikiedu08idn Rafikiedu08idn · Answer 1 · 2022-12-06T03:07:30-05:00

The structure of the acetyl-CoA is -[SEE aatachemt]

The structure of the malonyl-CoA is -[SEE aatachemt]

The structure of the palmitic acid is -[SEE aatachemt]

So from comparing all the three structures, it is evident that the terminal carbon with attached O= will be the suitable carbon to radiolabel the malonyl-CoA as this carbon will remain in the resultant palmitate molecule to trace down.

A crucial intermediary metabolite in the synthesis of fatty acids is malonyl-CoA. Malonyl-coenzyme A (CoA) is the substrate that serves as the main carbon source for the synthesis of palmitate (C16), which is catalyzed by fatty acid synthase, in de novo fatty acid synthesis.

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