Answered

Join the growing community of curious minds on IDNLearn.com and get the answers you need. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.

learning goal: to understand the role of friction in a state of equilibrium. a chair weighing 70.0 n rests on a level floor that is not frictionless. a man pushes on the chair with a force f

Sagot :

Tutorconsortium109idn
  1. The magnitude of the normal force that the floor exerts on the chair is 93.79 N
  2. coefficient of static friction μ is 0.32

What is coefficient of static friction?

  • The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. The formula fr = Fr/N serves as a representation of it.
  • "The highest ratio of applied force to normal force with no motion is called the coefficient of static friction." We all understand that a force called friction resists motion. If we carefully notice, there is a point at which the body opposes movement after force is applied to move it from rest.
  • The things that are creating friction determine the coefficient of static friction's value. Its value typically ranges from 0 to 1, but it can also be higher than 1.

Given details :

  • Weight of chair W = 70 N
  • Force P = 39 N
  • Angle = 38°

1.Force equilibrium in x direction

∑ [tex]F{x}[/tex] = 0

F - 39 cos Ф = 0

As Ф = 38°

F = 39 cos38°

F = 30.73 N

Force equilibrium in y direction

∑ [tex]F{y}[/tex] = 0

N = W + P sin38°

   =  70 + 39 sin38°

N = 93.79 N

Thus the normal force on chair = 93.79 N

From the free body diagram

F = μN

30.73 = μ x 93.79

μ = 30.73 / 93.79 = 0.32

Learn more about coefficient of static friction refer to :

https://brainly.com/question/25534663

#SPJ1

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. For dependable and accurate answers, visit IDNLearn.com. Thanks for visiting, and see you next time for more helpful information.