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in a random sample of 38 restaurants it was found that the mean number of employees was 12.6 with a standard deviation of 2.4 employees. find the critical value used to test the claim that the mean number of restaurant employees is less than 15 at the 1% significance level.

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Critical value used to test the claim that the mean number of restaurant employees is less than 15 at the 1% significance level is - 2.431

What is standard Deviation ?

The square root of the variance is used to calculate the standard deviation, a statistic that gauges a dataset's dispersion from its mean. The variation from the mean of each data point is used to determine the standard deviation, which is equal to the square root of variance.

What is mean ?

It is basically the average of the given numbers.

The given data is

Sample Size = n = 38

Sample mean = X = 12.6

Sample Standard deviation = S = 2.4

= n - 1 = 38 - 1 = 37

μ₀ = μ ≥ 15

μ₁ = μ < 15 ( left tailed )

d = 0.01

Hence, Critical value = - 2,431

To learn more about Statistics, Visit :

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