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350 ml of NaCl solution made by combining 9. 3 g of NaCl with enough water to dissolve it has a 0.458M molarity.
The solution is represented by molarity.
M stands for "molarity," which is the amount of solute in moles per liter of solution.
The formula for calculating molarity is
M = moles of solute/liter of solution.
The mass of NaCl is 9.3 g, the volume of the solution is 350 mL, and the volume of the solution in liters is given by 350/1000, or 0.35 L.
M = moles of NaCl/liter of solution is the formula used to calculate M.......... (1)
Therefore, we must first determine the moles of NaCl.
Molar mass (NaCl)/mass of NaCl = moles of NaCl...... (2)
NaCl's molar mass is 58 g/mol.
Add values to Eq (2)
NaCl moles are 9.3 g/58 g/mol.
NaCl moles equal 0.16 mol.
Place the numbers in Eq. (1) as follows:
M = 0.16 mol/0.35 L
M = 0.458
The Molarity then equals 0.458M.
The molarity is 0.458M as a result.
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