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The instantaneous rate of change is the change in the rate at a particular instant and it is same as the change in derivative value at a specific point.
From the above given data, the following solution is given below:
Given:
Let f(x,y,z) = x³z - yz²
To find the partial derivatives of f
Here the directional derivative of a function f(x,y,z) is given by:
(df/dx , df/dy, df/dz)
df/dx = 3x²
df/dy = -z²
df/dz = x³ - 2yz
at points(1,3,2)
(df/dx)₍₁,₃,₂₎ = 3(1)² = 3
| (df/dx)₍₁,₃,₂₎ | = 3
(df/dy)₍₁,₃,₂₎ = -2² = 4
| (df/dy)₍₁,₃,₂₎ | = 4
(df/dz)₍₁,₃,₂₎ = 1³ - 2*3*2 = 1-12 = -11
| (df/dz)₍₁,₃,₂₎ | = 11
As we got the maximum modulus of derivative in direction of x. Since, therefore we should move into z direction to maximize the directional derivative.
(df/dz)₍₁,₃,₂₎ = -11
Hence, the instantaneous rate of change is the change in the rate at a particular instant and it is same as the change in derivative value at a specific point.
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The instantaneous rate of change is the change in the rate at a particular instant and it is same as the change in derivative value at a specific point.
What is instantaneous rate of change?
The derivative value change at a particular point is the same as the instantaneous rate of change, which is the change in rate at a specific instant. The tangent line slope and the instantaneous rate of change at a given point on a graph are the same. That is, the slope is curved.
From the given data, the solution is given below:
Given:
Let f(x, y, z) = x³z - yz²
To find the partial derivatives of f
Here the directional derivative of a function f(x, y, z) is given by:
(∂f/∂x , ∂f/∂y, ∂f/∂z)
∂f/∂x = 3x²
∂f/∂y = -z²
∂f/∂z = x³ - 2yz
at points(1,3,2)
(∂f/∂x)₍₁,₃,₂₎ = 3(1)² = 3
| (∂f/∂x)₍₁,₃,₂₎ | = 3
(∂f/∂y)₍₁,₃,₂₎ = -2² = 4
| (∂f/∂y)₍₁,₃,₂₎ | = 4
(∂f/∂z)₍₁,₃,₂₎ = 1³ - 2*3*2 = 1-12 = -11
| (∂f/∂z)₍₁,₃,₂₎ | = 11
As we got the maximum modulus of derivative in direction of z. Since, therefore we should move into z direction to maximize the directional derivative.
(∂f/∂z)₍₁,₃,₂₎ = -11
Hence, the instantaneous rate of change is the change in the rate at a particular instant and it is same as the change in derivative value at a specific point.
To know more about instantaneous rate of change, click on the link
https://brainly.com/question/24592593
#SPJ4
Complete question:
Complete question is attached below.


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