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how many grams of nacl must be combined with water to prepare 510 ml of a 0.95 % (m/v) physiological saline solution?

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Bharathparasad577idn

4.84 grams of NaCl must be combined with water to prepare 510 ml of a 0.95% (m/v) physiological saline solution.

                                                                   

The ratio of the mass of the solute present in a solution to the volume of the solution as a whole is known as the mass/volume percent. The given proportion must be multiplied by 100 because this sort of concentration is expressed as a percentage.

Let number of grams of NaCl  combined with water to prepare 510 ml be x grams.

The mass/ volume percent of this solution ⇒ [tex]\frac{x}{510} *100 = 0.95[/tex]

                                                                   ⇒ [tex]x= \frac{0.95}{100} * 510[/tex]

                                                                   ⇒ [tex]x[/tex] = [tex]4.84[/tex]

Therefore, 4.84 grams of NaCl must be combined with water to prepare 510 ml of a 0.95% (m/v) physiological saline solution.

To learn more about mass by volume refer-https://brainly.com/question/28941273

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