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Therefore the solution to this question of 2 pulleys is )16 rpm
b)360 rad/min c)39.6 rad/min d) 7200cm/min
A pseudovector used in physics to express how quickly an object's angular position or orientation changes over time is called an angular velocity, rotational velocity, or angular frequency vector.
For the smaller pulley, it does 48 rpm (revolutions per minute) each revolution is 360 degrees. This indicates that the pulley completes one revolution every second .
radians / π = degrees / 180
radians = πx 360 / 180 = 2 π radians per second
The distance covered by both pulleys is equivalent for the larger pulley.
then d1 = d2
every second, small pulley covers a distance of 40π (small pulley circumference) = d1
d2 = 40π = 120π (large pulley circumference) x factor (f)
f = 1/3
a) the revolutions per min by larger pulley=16 rpm
b) the speed of smaller pulley = 3*2π=6π=6rad/sec=360rad/min
c) then speed of the large pulley = 1/3 * 2π = 2/3 π = 0.66 rad/sec=39.6rad/min
d)the speed of smaller pulley=7200 cm/min
Therefore the solution to this question of 2 pulleys is )16 rpm
b)360 rad/min c)39.6 rad/min d) 7200cm/min
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