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How many solutions does the following equation have?
-14(z-5) = -14z +70
Choose 1 answer:
A. No solutions
B. Exactly one solution
C. Infinitely many solutions


Sagot :

Phuchoangidn

Answer: C. Infinitely many solutions

Step-by-step explanation: If the answer is <0, then there is no solution; if it is >1, then there is more than one solution; if = 0, then there are Infinitely many solutions

-14(z-5) = -14z +70 can be write as

-14z + 70 = -14z + 70

-14z = -14z

 z= 0

Because the answer is 0 so there Infinitely many solutions

If you can, please give me a Brainliest; thank you!

AnimeBrainlyidn

Answer:

C. Infinite many solutions.

Step-by-step explanation:

Simplify the left side of the equation. Note the parenthesis. Distribute -14 to all terms within the parenthesis:

-14(z -  5) = -14z + 70

-14z + 70 = -14z + 70

C. Infinitely many solutions is your answer, as no matter what number you plug in for the variable z, the equation would still be true.

Learn more about amount of solutions, here:

https://brainly.com/question/13712241

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