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Sagot :
Answer:
see attached
Step-by-step explanation:
Given the equation for a line, y +3 = (x -6), you want to identify the slope and a point on the line, then graph it.
Point-slope form
The point-slope form of the equation for a line is ...
y -k = m(x -h) . . . . . . . . line with slope m through point (h, k)
Comparing this to the given equation, you can see ...
- k = -3
- m = 1 . . . . . . . . . . a coefficient of 1 is often "missing" or "implied"
- h = 6
This tells you the slope is 1 and a point on the line is (6, -3).
Graph
You graph this equation by plotting point (6, -3) and drawing a line through it that goes up 1 unit for each 1 unit to the right. A graph is attached.
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Additional comment
If you like, you can rearrange the equation to slope-intercept form by subtracting 3:
y +3 -3 = (x -6) -3
y = x -9
This tells you another point is -9 on the y-axis.

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