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Aume that 437. 7 j of heat i added to 5. 00 g of water originally at 23. 0C what would be the final temperature of the water

Sagot :

The final temperature of the water is 43.92°C.

What is specific heat capacity?

The specific heat is defined as amount of energy in the form of heat to change heat content of 1 gram of substance by one-degree Celsius temperature.

Specific heat capacity of water = 4.184J/g°C

heat (q) = 437.7 J

Initial temperature = 23°C

Final temperature = T

mass of water = 5.00g

using the equation: q= mₓcₓΔT

437.7 = 5ₓ4.184ₓ(T- 23.0)

(T-23.0) = 437.7/ (5ₓ4.184)

T= 23.0°C +20.92°C = 43.92°C

T= 43.92°C

For more information about specific heat capacity please visit:

https://brainly.com/question/26378808

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