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Using trigonometric ratio, the length of BE is 10 units, the value of sin B is 0.64 and cos B is 0.64 respectively
This is the ratio between the angles and sides of a right-angle triangle. The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).
In this problem, we have that
1)
Using tangent of B
tan B = opposite / adjacent
tan B = NE / BE
3/4 = 7.5 / BE
BE = 7.5 / 0.75
BE = 10
2)
To find sin B, we need to calculate the hypothenuse of the triangle which we will use Pythagoras's theorem
NB² = BE² + NE²
NB² = 10² + 7.5²
NB = 12.5
sin B = NE / NB
sin B = 7.5 / 12.5
B = sin⁻¹ (7.5 / 12.5)
B = 0.64
3)
cos B = BE / NB
cos B = 10 / 12.5
B = cos⁻¹ (10/12.5)
B = 0.64
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