Answered

Join the conversation on IDNLearn.com and get the answers you seek from experts. Ask your questions and receive comprehensive and trustworthy answers from our experienced community of professionals.

The following data were obtained on the initial rates of a reaction of a d-metal complex in aqueous solution. What is (a) the order of reaction with respect to the complex and the reactant Y, (b) the rate constant? For the experiments a [Y]=2.7 mmol dm 3 and for experiments (b) [Y]=6.1 mmoldm (complex]/(mmol dm-3) v/mol dm-35-1) (a) (b) 8.01 125 640 9.22 144 730 12.11 190 960

Sagot :

a) The order of the reaction with respect to the complex is 1 and order with respect to Y is 2.

b) The rate constant for reaction is 2.2 × 10⁹ mol⁻²dm⁶s⁻¹.

What is order of reaction and rate constant?

The order of reaction is defined as sum of the power raised to the concentration terms . The rate constant defined as the relation between concentration and rate of the reaction, and it is also temperature dependent.

Using Rate = K [complex]ᵃ [Y]ᵇ

a)  125 = K (8.01) ᵃ (2.7) ᵇ

144= K (9.22) ᵃ (2.7) ᵇ

Divide these two equations

125/144 = (8.01/ 9.22) ᵃ

(0.868) = (0.868) ᵃ

⇒ a= 1 order with respect to complex is 1

b)  R₂=K(complex)ᵃ(Y)ᵇ

125=K (8.01) (2.7) ᵇ

640=K (8.01) 6.1) ᵇ

Divide these two equations

we get, 0.195 = (0.443)ᵇ

⇒ b= 2 order with respect to Y is 2.

Now Rate constant

125=K (8.01) ¹ (2.7) ²

K = 2.2 ₓ 10⁹mol⁻²dm⁶s⁻¹.

For more information about rate of reaction please visit:

https://brainly.com/question/15269961

#SPJ4

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.