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Sagot :
16.2 kJ heat is required to change 48.5 liquid (Hg) at 400 K to vapor at a 700 K.The quantity of heat required to raise the temperature of a substance by one degree Celsius is known as the specific heat capacity.
How to solve?
Q = m * cl * ( T f - T i ) + mL + m * cv *T (f) - T (i)
Q = Heat absorbed = ?
m= mass of mercury (Hg)= 48.5 g = 0.0485 kg
c = specific heat capacity = 14.31kj/kgK
L = Latent heat of vaporization = 59.2 kJ
Initial temperature of liquid mercury = T i = 400 K
Final temperature of mercury vapor = T f = 700 K
Putting in the values, we get:
Q=1.56+14.31+0.34
Q=16.2kJ
How is vapor pressure determined at various temperatures?
Result for an image mercury's vapor pressure at various temperatures. Use the Clausius-Clapeyron equation to determine the vapor pressure at a specific temperature: ln(P1/P2) = (Hvap/R)((1/T2) - (1/T1)
What degree of heat does mercury evaporate at?
The only metal that is liquid at ambient temperature is mercury. When it is over its freezing point, it melts and evaporates like all liquids do. Since mercury has a freezing point of only 37.6°F, it is constantly evaporating.
Learn more about Clausius-Clapeyron equation here:
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