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A capacitor is connected to an AC source. If the maximum current in the circuit is 0.400 A and the voltage from the AC source is given by Δv = (82.8 V) sin[(86π)s−1t], determine the following.
a) the rms voltage (in V) of the source
b) the frequency (in Hz) of the source
c)the capacitance (in µF) of the capacitor

Sagot :

The RMS Voltage , Frequency and capacitance of capacitor is 82.8V,6.28Hz and 2.34F

  • Because the RMS value provides the amount of AC power drawn by a resistor that is comparable to the power drawn by a DC source, the RMS voltage is also referred to as the equivalent DC voltage.
  • Consider a 10V DC source and a 5 load as an example. When using a DC source, the voltage value remains constant throughout all time.
  • A potential difference is created across the capacitor by the buildup of charges in the conductors. The capacitor's capacity to hold a charge is determined by how much charge has accumulated.
  • Capacitance is the name for this ability to hold a charge. The voltage created across the capacitor is directly proportional to the charge that has built up in the capacitor.

Q ∝V .

Q = C/V.

C = Q/V.

  1. RMS voltage =82.8V
  2. Frequency=2πw=2 x 3.14 x 1 =6.28Hz
  3. capacitance=86/82.8=2.34 F

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