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Sagot :
Required equation of the parabola with origin as its vertex and directrix
y = 1/2 is equal to x² = -2y.
As given in the question,
Let vertex of the parabola be ( h, k )
Vertex of the given parabola be at origin
⇒ ( h , k ) = ( 0 , 0 )
Directrix is y =1/2 above the vertex.
Focus is ( 0, -1/2)
Equation of the parabola is given by
Distance between focus to the vertex = distance between vertex to the directrix
( y - (1/2) )² = ( x - 0)² + ( y - (-1/2) )²
⇒ y² - y + 1/4 = x² + y² + y + 1/4
⇒ -y = x² + y
⇒x² = -y - y
⇒ x² = -2y
Therefore, the equation of the parabola with vertex at origin and directrix y =1/2 is equal to x² = -2y .
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