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what is the resonance frequency if the capacitor value is doubled and, at the same time, the inductor value is halved?

Sagot :

The resonance frequency will remain the same if the capacitor value is doubled and, at the same time, the inductor value is halved.

The resonant frequency is a term used to describe the oscillation of a system at its natural or unforced resonance.

In an LC circuit, the resonance frequency can be determined by the following equation;

ω = 1 / √LC

Here L represents the inductor value and C illustrates the value of the capacitance.

If the capacitance is doubled, C'=2C, and the inductance is halved, L'=L/2, then;

ω = 1 / √L'C'

ω = 1 / √(L/2) × (2C) = 1 / √LC = ω

Therefore the frequency of resonance is equal to the original value.

To learn more about resonance frequency; click here:

https://brainly.com/question/13040523

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