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a certain isotope decays at a rate such that it loses 15% of its mass every second. find the equation of the form

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The equation of the form of isotope is M(n) = (1 - 15%)ⁿ M grams. Where M is the initial mass of an isotope.

If the initial mass of an isotope is M grams and every second it loses 15%, it means the remaining of an isotope

  • After 1 s
    M(1) = M - 15% M
    M(1) = M - 0.15M
    M(1) = 0.85M
  • After 2 s
    M(2) = 0.85M - 15% (0.85M)
    M(2) = 0.85M (1 - 15%)
    M(2) = 0.85M (100% - 15%)
    M(2) = 0.85M × 0.85
    M(2) = 0.85² M
  • After 3 s
    M(3) = 0.85² M - 15% (0.85² M)
    M(3) = 0.85² M (1 - 15%)
    M(3) = 0.85² M × 0.85
    M(3) = 0.85³M
  • After n s
    M(n) = 0.85ⁿ M
    M(n) = (1 - 15%)ⁿ M

Learn more about an isotope decays here : https://brainly.com/question/16403276

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