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What i the lope of a line perpendicular to the line whoe equation i 3x-6y=90. Fully implify your anwer

Sagot :

The slope of line perpendicular to line 3x - 6y = 90 is -2.

Slope-Intercept form of equation => y = mx + c

Slope = m

Given equation,

3x - 6y = 90

 x - 2y = 30

      2y = x - 30

        y = x/2 - 15

        y = (1/2)x + (-15)

Here, slope = m1

                   = 1/2

For line perpendicular slope will be negative reciprocal of the slope of given line.

Therefore, slope of other line = m2

                                                 = -1/m1

                                                 = -2

Hence, slope of line perpendicular to line 3x - 6y = 90 is -2.

To learn more about slope here:

https://brainly.com/question/3605446

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