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Sagot :
The truth value of the ~[P v (Q v R)] >~ (S v P) is true.
Truth-value, in logic, is the degree to which a particular proposition or assertion is true (T or 1) or false (F or 0). Because the truth-value of a compound proposition is a function of, or a quantity depending upon, the truth-values of its component components, logical connectives like disjunction and negation can be conceived of as truth-functions.
Given, ~[P v (Q v R)] >~ (S v P) since P v (Q v R) is true, thus ~ [ P v ( Q v R ) ] is false, therefore the implication is true.
⇒~[T v (F v T)] >~ (F v T)
⇒[F v (F v T)]>(T v T)
⇒[F v (F v T)]>(T v T)
⇒F v T
⇒T
To know more about truth value visit: brainly.com/question/18994288
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