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let be a diagonalizable matrix. if is the solution to the system , then check all the possible values of and below. (a); (b) ; (c) ; (d) ; (e) ; (f) .

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Let A be a diagonalizable matrix. If c₁ and c₂ are solution to system

x⃗' (t) = A x⃗ ( t )

the possible values of c₁ is 1 and c₂ is 2 .

So, the correct option is option(a) and (e).

We have given that A is 2 × 2 diagonalizable matrix and x⃗ (t) = ( 3eᵗ + eᶜ₁t , 3e²ᵗ + eᶜ₂ᵗ) is a solution of system, x⃗ '(t) = A x⃗(ᵗ) .

A Solution of system always satisfied the equation of system.

Now, Differenating x⃗ (t) wih respect to t we get, x⃗' (t)=( 3eᵗ + c₁ eᶜ₁t , 6e²ᵗ + c₂ eᶜ₂ᵗ)

So, ( 3eᵗ + c₁ eᶜ₁t , 6e²ᵗ + c₂ eᶜ₂ᵗ)= A ( 3eᵗ + eᶜ₁t , 3e²ᵗ + eᶜ₂ᵗ) where A is diagonalizable and A = [a 0 0 b].

Then, ( 3eᵗ + c₁ eᶜ₁t , 6e²ᵗ + c₂ eᶜ₂ᵗ) = ( 3aeᵗ + aeᶜ₁t , 3be²ᵗ + b eᶜ₂ᵗ)

equating the coefficients on both sides we get, 3eᵗ + c₁ eᶜ₁t = 3aeᵗ + aeᶜ₁t 6e²ᵗ + c₂ eᶜ₂ᵗ = 3be²ᵗ + b eᶜ₂ᵗ

after equating the corresponding equations , 3 = 3a and c₁ = a and 6 = 3b and c₂ = b after solving all we get a = 1 and b = 2 which implies c₁ = 1 and c₂ = 2. Hence, the possible values are c₁ = 1 and c₂ = 2.

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Complete question:

Let A be a diagonalizable matrix. If c₁ and c₂ are solution to system x⃗ (t) = A x⃗

then check all the possible values of c₁ and c₂ and below.

(a) c₁ = 1

(b) c₁ = 3

(c) c₁ = 2

d) c₂ = 1

(e)c₂ =2

(f) c₂ = 3

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