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the de broglie wavelength of a 0.0810 gram bullet traveling at the speed of 658.3 m/s is m.

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The de broglie wavelength of the bullet of mass 0.081 g is 1.24×10⁻³⁸ m

What is wavelength?

Wavelength is the distance between identical points (adjacent crests) in the adjacent cycles of a waveform signal propagated in space or along a wire.

To calculate the  de broglie wavelength, we use the formula below.

Formula:

  • λ = h/mv................... Equation 1

Where:

  • λ = de broglie wavelength of the bullet
  • m = Mass of the bullet
  • v = Velocity of the bullet
  • h = Planck's constant

From the question,

Given:

  • h = 6.62×10⁻³⁴ J/Hz
  • m = 0.081   = 0.000081 kg
  • v = 658.3 m/s

Substitute these values into equation 1

  • λ = (6.62×10⁻³⁴)/(0.000081×658.3)
  • λ = 1.24×10⁻³⁸ m

Hence, the de broglie wavelength of the bullet is 1.24×10⁻³⁸ m

Learn more about wavelength here: https://brainly.com/question/10728818

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