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Sagot :
The density of the metal with an edge length of 495.08pm is 549.06pm
Lead crystallizes with FCC lattice, Z = 4
√2a = 4r
r = 175.01pm
The density is given as:-
D=ZM/N0(a3) =5.616
Edge length a=404.91pm
For a BCC lattice, the 3D diagonal (l) and edge length (a) is related as:-
l=√3al=1.732×317=549.06pm
The density (d) of a crystal depends on the number of atoms occupying each unit cell, the mass of each atom (m), and the edge length of the unit cell (a). There are three types of cubic lattices,
1. Simple Cubic
2. Body centered
3. Face centered
Find more about lead crystal:-
brainly.com/question/14786159
#SPJ4
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