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Let E be the event that a corn crop has an infestation of ear worms, and let B be the event that a corn crop has an infestation of corn borers. Suppose that P(E) = 0.24, P(B) = 0.16, and P(E and B) = 0.13. Find the probability that a corn crop has either an ear worm infestation, a corn borer infestation, or both.0.530.130.60.27

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The probability that a corn crop has either an ear worm infestation, a corn borer infestation, or both is 0.27.

What is probability?

The area of mathematics known as probability deals with numerical descriptions of how likely it is for an event to happen or for a proposition to be true. A number between 0 and 1 is the probability of an event, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes its certainty.

We have to find the probability that a corn crop has either an ear worm infestation, a corn borer infestation, or both.

Since,

P(E or B) = P(E) + P(B) - P(E and B)

Given,

P(E) = 0.24

P(B) = 0.16

P(E and B) = 0.13

Hence,

P(E or B) = 0.24 + 0.16 - 013

P(E or B) = 0.27

Option D is correct.

Hence, the probability that a corn crop has either an ear worm infestation, a corn borer infestation, or both is 0.27.

To know more about probability, click on the link

https://brainly.com/question/24756209

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