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Volume of 0.20 M sodium acetate is calculated to be 0.82g. Sodium acetate can be used as additives in food, industry and in buffer solutions.
To determine pH of a buffer is by using the Henderson–Hasselbalch equation is pH = pKₐ + log([A⁻]/[HA]).
As we know that, pH = pKa + log [salt]/[acid]
Given pH (4.75) and pKa (4.75).
Given [acid] = 0.20 M
When the pH = pKa, ratio of [salt]/[acid] =1 because log 1 = 0
Hence,[sodium acetate] = 0.20 M.
4.75 = 4.75 + log [sodium acetate]/[0.20]
0 = log x/0.2
Hence, x = 0.2 M
To calculate the "amount" in grams, convert 0.20 M to grams using the volume of 50 ml (0.05 L)
0.20 mole/L x 0.05 L = 0.01 moles moles sodium acetate
0.01 moles sodium acetate x 82 g/mole
Volume of 0.20 M sodium acetate= 0.82g
To know more about Henderson-Hasselbalch equation, refer
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