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Use separation of variables to find the solution to the differential equation subject to the given initial condition.
dP/dt=0.07P, P(0)=30


Sagot :

The solution to the differential equation subject to the given initial condition is  log P = 0.07t + log(30)

Differential equation in which the variables can be separated from one from one another are called separable differential equations

A general form to write a separable differential equation is

dy/dx = f(x)g(y)

where the variable x and y can be separated from each other

According to the question,

We have to solve dP/dt=0.07P by using separation of variable

=> dP/dt=0.07P

Dividing P both sides and multiplying dt

=> dP / P = 0.07 dt

Now Integrating both the sides

=> [tex]\int\limits {\frac{1}{P} \, dP = \int\limits {0.07} \, dt[/tex]

=> log P = 0.07t + c ------(1)

It is given that  P(0)=30

which means at t = 0 , the value of P = 30

Substituting t = 0 and P = 30

log(30) = 0 + c

=> c = log(30)

Substituting the value of c back to equation (1)

log P = 0.07t + log(30)

=> log(P / 30) = 0.07t is our solution

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