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Write the equation in standard form for the circle that has a diameter with endpoints (-2,10) and (-2,8)

Sagot :

The equation in standard form for the circle will be;

⇒ (x + 2)² + (y - 9)² = 1

What is Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

The circle that has a diameter with endpoints (-2,10) and (-2,8).

Now,

Since, The circle that has a diameter with endpoints (-2,10) and (-2,8).

Hence, The radius of circle is the half of the distance between two points of the diameter.

So, Radius = 1/2 (√ (8 - 10)² + (- 2 - (-2))²

                 = 1/2 √4

                = 1/2 × 2

                 = 1

Thus, Radius (r) of circle = 1

And, The center of circle is midpoint of the endpoints of the diameter.

Hence, Centre = (- 2 + (-2))/2, (10 + 8)/2

                       = - 4/2 , 18/2

                       = (- 2, 9)

Hence, The equation of circle with center (-2, 9) and radius 1 is;

⇒ (x - (-2))² + (y - 9) = 1²

⇒ (x + 2)² + (y - 9)² = 1

Thus, The equation in standard form for the circle will be;

⇒ (x + 2)² + (y - 9)² = 1

Learn more about the circle visit:

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