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Sagot :
B= ½ [U₀I/2a-U₀I/2b) out= U₀I/4 [1/a – 1/b] out = B
The magnetic field from the circle of a wire is B = U₀I/2R
Therefore there are 2 half circles. The out circle makes the B field into the page at the point P and the inner circle is making the field out of the page. To easily see this, the best thing to use is an RHR. Thus, subtraction is applied. The two straight wire lengths are not contributing to this filed because they seem to be running into/out of P. This means that r and I are parallel, thus the cross-product in Biot-Savart calculation will got to zero.
The answer be written down (this is after discovering that there are 2 half circles):
B= ½ [U₀I/2a-U₀I/2b) out= U₀I/4 [1/a – 1/b] out = B
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