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Sagot :
q = 40 is the value of q in quadratic equation.
What is quadratic equation explain?
The equation x ax2+bx+c=0 is a quadratic equation, which is a second-order polynomial equation in a single variable. with a ≠ 0 .
The fundamental theorem of algebra ensures that it has at least one solution because it is a second-order polynomial equation. The answer could be simple or complicated.
the roots of a quadratic expression
ax² + bx + c = 0
Since x' and x'' are the roots of this equation, then we can write the Vieta's formula
x' + x'' = -b/a
x' * x'' = c/a
let's replace the 2nd equation of the Vieta's formula by that and make it a Linear System.
x' + x'' = 14/1
x' * x'' = 6
after solve the equations
x' = 10
Solving the equations
10 + x''=14
x'' = 4
Since we have a=1
x^2-14x + q = 0
Then we can make q as the parameter c.
q = x' * x'' = 4 * 10 ⇒ 40
x2−14x+ 40 = 0
Learn more about quadratic equation
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The complete question is -
The difference between the roots of the quadratic equation x2−14x+q=0 is 6. Find q.
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