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To create 11.5 litres of Ringer's lactate, 4.19 gram of sodium lactate is required per the question.
In the some nuclear reactor, sodium is employed as a heat exchanger. It is also utilized as a reactant in the chemical sector. In contrast, sodium salts are more useful than sodium itself. Sodium chloride is the most prevalent sodium compound (common salt).
Concentration of NaC₃H₅O₃ = 3.25mM
= 3.25*10⁻³M
Volume = 11.5 litre
Molar mass of NaC₃H₅O₃ = 112g/mol
No. of moles of NaC₃H₅O₃
= Concentration of NaC₃H₅O₃ * volume
= 3.25*10⁻³ * 11.5
= 37.38*10⁻³
=3.738*10⁻²
0.037 mol
Therefore,
Mass of NaC₃H₅O₃
= No. of moles of NaC₃H₅O₃ * Molar mass of NaC₃H₅O₃
= 0.037*112
= 4.19 grams
Hence, the required mass of NaC₃H₅O₃ is 4.19 g
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The complete question is-
An aqueous solution known as Ringer's lactate is administered intravenously to trauma victims suffering from blood loss or severe burns. The solution contains the chloride salts of sodium, potassium, and calcium and is also 3.25 mM in sodium lactate (NaC₃H₅O₃).
How many grams of sodium lactate are needed to prepare 11.5 liters of Ringer's lactate?