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A certain brand of freezer is advertised to use 880 kW*h of energy per year.

A) Assuming the freezer operates for 6 hours each day, how much power does it require while operating?

P= ?

B) If the freezer keeps its interior at a temperature of -6.0?C in a 20.0 ?C room, what is its theoretical maximum performance coefficient?

K= ?

C) What is the theoretical maximum amount of ice this freezer could make in an hour, starting with water at 20.0 ?C?

m= ?


Sagot :

If the freezer operates for 6 hours each day then the power it requires for operating is (p) = 401.82W

If the freezer keeps its interior at a temperature of -6.0C in a 20.0C room, the theoretical maximum performance coefficient is (k) = 7.1

the theoretical maximum amount of ice this freezer could make in an hour, starting with water at 20.0C(m) = 24.58Kg

(a) Given energy of freezer (E) per year= 880 kW*h = 880x10^3 w*h

Time to operate = 6hrs per day

Power (P) = 880x10^3/(365x6) = 880x10^3/2190 = 401.82W

(b) Given T = -6+273 = 257K and T' = 20+273 = 293K

Coefficient(k) = T/T'-T = 257/293-257 = 7.1

(c) Q = mCwdT+mL

Q = 1kg(4190)(293-273)+1kg(3.34x10^3) = 417800J

heat removal(Qrem) = powerxk

Qrem = 401.82x7.1 =2852.922J

Mass of ice = Qrem/Q = 2852.922x3600/417800 = 24.58kg

To learn more about energy click here https://brainly.com/question/1932868

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