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Sagot :
The oxidation state of phosphorus in the compound P₄O₆ is +3.
In order to find the oxidation state of phosphorus in the compound P₄O₆,
we can assume the oxidation state of phosphorus to be X.
Now, we know, the oxidation state of oxygen atom is +2.
The net charge on the compound is 0.
So, we can write the formula as,
4X + 6(-2) = 0
Now, solving further,
4X = 12
X = 3
So, we got the value of X to be +3, Hence the oxidation state of phosphorus in this compound is +3.
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